131. Palindrome Partitioning
Tapan Rachchh
1 min read
class Solution:
def partition(self, s: str) -> List[List[str]]:
def checkPalindrome(word):
return word == word[::-1]
ans = []
def backtrack(index, prev, temp):
nonlocal ans
if index >= len(s):
if checkPalindrome(prev):
ans.append(temp + [prev])
return
if checkPalindrome(prev):
backtrack(index + 1, s[index], temp + [prev])
backtrack(index + 1, prev + s[index], temp)
backtrack(1, s[0], [])
return ans
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