frozen sets pay no heed to order
Danny Crasto
1 min read
I superficially assumed a frozenset
accounts for the order of items it was constructed with such that the following assertion would fail.
assert(
frozenset([('a',1), ('b',1)]) == frozenset([('b',1), ('a',1)])
)
Thinking about it for a second, sets are unordered, hence the above assertion holds.
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Written by
Danny Crasto
Danny Crasto
I am developer/code-reviewer/debugger/bug-fixer/architect/teacher/builder from dubai, uae