Finding the Quadrant of a Point in Java

𝗜𝗻 𝗝𝗔𝗩𝗔 𝗳𝗼𝘂𝗻𝗱 𝘁𝗵𝗶𝘀 𝗽𝗿𝗼𝗯𝗹𝗲𝗺 𝗶𝗻𝘁𝗲𝗿𝗲𝘀𝘁𝗶𝗻𝗴 𝘁𝗼 𝗯𝗲 𝘀𝗼𝗹𝘃𝗲𝗱 ,so i did and learnt something-

𝗣𝗿𝗼𝗯𝗹𝗲𝗺:
The task was to identify whether the coordinate given by the user ,falls in the 1st, 2nd, 3rd, or 4th quadrant. Additionally, I needed to handle edge cases where the point might lie on the x-axis or y-axis.

𝗛𝗼𝘄 𝗶 𝗱𝗶𝗱 𝗶𝘁 :
One interesting aspect of this project was managing the input. The user enters coordinates in the format x, y (e.g., 1, 2). Using the split() method in Java, I was able to ignore the comma and correctly parse the coordinates as integers, actually what id did was to store entire coordinate in an array and then separate it with comma and then store in 2 elements of the array . This approach ensures that even with spaces around the comma, the program processes the input smoothly.

𝗖𝗼𝗻𝗱𝗶𝘁𝗶𝗼𝗻𝗮𝗹 𝗟𝗼𝗴𝗶𝗰: the heart of the program lies in the if-else statements, which determine the quadrant based on the signs of x and y, and then i made all possible combinations

𝗪𝗵𝗮𝘁 𝗜 𝗟𝗲𝗮𝗿𝗻𝗲𝗱 𝗨𝗻𝗶𝗾𝘂𝗲 (this is the only thing i learned unique because the if-else thing was cakewalk for me already)

Input Parsing: Handling user input effectively is crucial, especially when it involves common delimiters like commas. This approach helped me better understand how to clean and parse input data.