2022. Convert 1D Array Into 2D Array
Tapan Rachchh
1 min read
class Solution:
def construct2DArray(self, original: List[int], m: int, n: int) -> List[List[int]]:
idealSize = len(original)
if m * n != idealSize:
return []
arr = [[0 for _ in range(n)] for _ in range(m)]
index = 0
for i in range(m):
for j in range(n):
if index < idealSize:
arr[i][j] = original[index]
index += 1
return arr
0
Subscribe to my newsletter
Read articles from Tapan Rachchh directly inside your inbox. Subscribe to the newsletter, and don't miss out.
Written by