🔐 Understanding and Implementing an N-Input AND Gate in C++


🧠 What is an AND Gate?
In digital logic, an AND gate is a basic logic gate that outputs:
1
(True) only if all of its inputs are 10
(False) if even one input is 0
🔧 Truth Table for 2-input AND Gate:
A | B | A AND B |
0 | 0 | 0 |
0 | 1 | 0 |
1 | 0 | 0 |
1 | 1 | 1 |
For more than two inputs, the same principle applies — all must be 1 for the result to be 1.
🧩 Problem Statement
💬 Question:
Construct an N-input AND Gate in C++.
Input: First line has an integer N. Second line has N binary integers (0 or 1).
Output: 1 if all inputs are 1, otherwise 0.
🧾 Example:
Input:
4
1 1 1 0
Output: 0
Why? Because one of the inputs is 0
, and the AND gate fails if any input is 0
.
🧮 Real-World Analogy
Imagine a team project where every member must submit their part.
If even one person fails to submit, the project fails.
That’s exactly how an AND gate behaves — all must be 1
(submitted) to succeed.
🧑💻 Approach
Read the number of inputs
N
.Initialize a variable
result = 1
(we assume all are 1 to begin with).Loop through all inputs and update
result
using bitwise AND:result = result & input;
If any input is
0
, result will become0
.Finally, print the
result
.
💻 C++ Code
Output
🔍 Why Bitwise AND Works Here
The bitwise AND (&
) compares two bits and returns:
1
if both are1
0
otherwise
So when we keep doing result = result & input
, if even one input is 0, the whole result becomes 0.
This is faster and cleaner than using if
conditions.
🧮 Dry Run Example
Input:
n = 4
values = 1 1 1 0
Step | Input | Prev Result | result & input | New Result |
1 | 1 | 1 | 1 & 1 = 1 | 1 |
2 | 1 | 1 | 1 & 1 = 1 | 1 |
3 | 1 | 1 | 1 & 1 = 1 | 1 |
4 | 0 | 1 | 1 & 0 = 0 | 0 |
✅ Final Output: 0
Reason: One of the inputs is 0 → AND gate outputs 0
🧠 Bitwise AND (&
) Logic
1 & 1 = 1
1 & 0 = 0
0 & 0 = 0
The AND gate fails if even one input is 0, which is exactly how &
behaves in C++.
⏱️ Time & Space Complexity
Time Complexity:
O(N)
Space Complexity:
O(1)
🧪 Sample Test Cases
✅ Test 1:
Input:
3
1 1 1
Output: 1
❌ Test 2:
Input:
5
1 1 0 1 1
Output: 0
⚠️ Edge Case:
Input:
1
0
Output: 0
📌 Conclusion
Simulating an AND gate in C++ is a great way to understand both:
Basic bitwise operations
Logic simulation techniques used in hardware/software design
It’s also a common beginner-level coding problem asked in interviews and technical rounds.
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Written by

Neha Sharma
Neha Sharma
Hello, I'm Neha sharma and I'm final year master's student in nims university in the field of AI and ML. published 2 research paper and started youtube channel where we solve daily one programming question and understand the concept through question. I done 3 internship and 2 back to back participate and completed opensource contribution in hacktoberfest. i'm on linkedln with 1.1K+ followers. and i'm a freelencer in designing.