🧠 100 Lines of Well-Structured Code vs. 2 Lines of Cleverness

AmanAman
5 min read

πŸ“‘ Article Outline

  1. Introduction

  2. The Problem

  3. APPROACH 1: Efficient strategy. Benefits of Well-Structured Code

    β†’ Code

  4. APPROACH 2: Drawbacks of Clever Code

    β†’ Code

  5. Comparison Table

  6. Conclusion

  7. Final Thought

πŸ” Introduction

"Clever code is often the enemy of clear code."

In the tech community, developers sometimes celebrate brevity and trickery. β€œWow, that’s just 2 lines and does everything!” But is brevity always best?

This article dives into the trade-off between clear, well-structured code and overly clever one-liners. We'll explore the importance of writing code for efficiency, and why clarity nearly always trumps cleverness in the long run.

🎯 The Problem:

You have 9 identical-looking balls, but one of them is heavier than the others.
You are allowed to use a balance scale (that shows which side is heavier), and your goal is to find the heavy ball in the fewest number of weighings.

βš–οΈ APPROACH 1: Divide and Weigh (Efficient Strategy)

This is the most efficient and logical approach.

🧠 Step-by-step Process:

  1. Divide the 9 balls into 3 groups of 3 balls each:

    • Group A: Ball 1, 2, 3

    • Group B: Ball 4, 5, 6

    • Group C: Ball 7, 8, 9

  2. Weigh Group A vs Group B

    • βš–οΈ Place Group A on the left pan, Group B on the right pan.

βž• CASES:

βœ… Case 1: Balance is equal

  • Group A = Group B β†’ The heavier ball is in Group C.

  • Pick any two balls from Group C and weigh:

    • Ball 7 vs Ball 8.

    • If equal β†’ Ball 9 is heavy.

    • If not equal β†’ The heavier side has the heavy ball.

❌ Case 2: One side is heavier

  • Suppose Group A is heavier β†’ Heavy ball is in Group A.

  • Now weigh Ball 1 vs Ball 2:

    • If equal β†’ Ball 3 is heavy.

    • If one is heavier β†’ That one is the heavy ball.

βœ… Number of Weighings: 2

  • First weighing: Compare two groups of 3.

  • Second weighing: Compare 2 balls from the suspected group.

πŸ”’ Reliability: 100%

You guarantee to find the heavy ball in just 2 weighings, no guessing needed.

πŸ§‘πŸ»β€πŸ’» C++ Code Example

int nineBallSmartCode()
{
    int ball[9] = {1, 1, 1, 2, 1, 1, 1, 1, 1}; // Ball 3 is heavier (index 3)

    // First weighing: group1 (0,1,2) vs group2 (3,4,5)
    int group1 = ball[0] + ball[1] + ball[2];
    int group2 = ball[3] + ball[4] + ball[5];

    int heavyGroupStart = 6; // Default to group3 (6,7,8)

    if (group1 > group2)
        heavyGroupStart = 0; // group1 is heavy
    else if (group2 > group1)
        heavyGroupStart = 3; // group2 is heavy

    // Second weighing: compare two balls in the suspected group
    if (ball[heavyGroupStart] > ball[heavyGroupStart + 1])
        return heavyGroupStart;
    else if (ball[heavyGroupStart + 1] > ball[heavyGroupStart])
        return heavyGroupStart + 1;
    else
        return heavyGroupStart + 2;
}

🧱 APPROACH 2: Brute-Force / Trial-and-Error

This is a simpler (but slower) approach: compare one ball at a time against a known "normal" ball.

🧠 Step-by-step Process:

  1. Pick Ball 1 and Ball 2, weigh them.

    • If equal, both are normal.

    • Continue comparing Ball 3 vs Ball 1, Ball 4 vs Ball 1, and so on...

  2. As soon as one side is heavier, you’ve found the odd (heavy) ball.


❌ Number of Weighings: Up to 8

  • In the worst case, the heavy ball is the 9th one.

  • You’ll have done 8 comparisons before reaching it.

πŸ”“ Reliability: 100%, but inefficient

  • You'll eventually find the heavy ball, but it could take up to 8 weighings.

βš™οΈ C++ Code Example

int nineBallShortCode()
{
    int ball[9] = {1, 1, 1, 2, 1, 1, 1, 1, 1}; // One ball is heavier
    int maxWeightIndex = 0;
    for (int i = 1; i < 9; i++)
    {
        if (ball[i] > ball[maxWeightIndex])
            maxWeightIndex = i;
    }
    return maxWeightIndex;
}

πŸ“Š Comparison Table

FeatureEfficient Divide MethodBrute-Force Method
Max Weighings Needed28
Speed⚑ Very Fast🐒 Very Slow
Logic RequiredModerateVery Simple
Reliabilityβœ… 100%βœ… 100%
Suitable forPuzzles, Smart SolutionsBeginners, Manual Checking

πŸ“Œ Conclusion & Key Takeaways

When solving tasks like finding a heavy ball, structured code offers clear logic and minimal steps, while clever code is compact but harder to follow.

  • Clarity beats cleverness when it comes to team-based, maintainable code.

  • Use structured logic when working on real applications or teaching.

  • Use short code only when the task is simple, isolated, and won’t change.

πŸ’‘ "Write code that humans can understand. Machines already do."

πŸ—£ Final Thought

β€œGood code isn't about writing lessβ€”it's about communicating more.”
A clever 2-liner might work once, but a thoughtful 100 lines will work forever.

πŸ’¬ Let’s Talk!

How do you balance clarity vs. cleverness in your code?
Drop a comment below or share your favorite β€œrefactor this!” moment. πŸ‘‡


✨ Bonus Tips for Formatting on Hashnode

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