Week 2: If you know Python, I need your Help!

This is An update of my week 2 of CS50. Which is now completed and i am about to move to Week 3 soon! there were 5 problems in Problem set 2 and i got all of them right after some iterations and polishing, except question no. 4 : Plates. I got only 8/9 correct evaluations however that’s it. I got a perfect score in all the other problems (6/6 , 10/10 and even 12/12).

Vanity Plates

In Massachusetts, the place that is home to Harvard University and MIT. It is possible to request for a custom Vanity plate for vehicles. However there are some rules or requirements that must be followed while creating your own license plate alphanumeric pattern.

Rules:

1. All vanity plates must start with at least two letters.

2. Vanity plates may contain a maximum of 6 characters (letters or numbers) and a minimum of 2 characters.

3. Numbers cannot be used in the middle of a plate; they must come at the end. For example, AAA222 would be an acceptable … vanity plate; AAA22A would not be acceptable.

4. The first number used cannot be a ‘0’. therefore AA022 is Invalid.

5. No periods, spaces, or punctuation marks are allowed

Examples that will be tested : (highlighted once are “Valid”

1. CS50

2. ECTO88

3. NRVOUS

4. CS05

5. 50

6. CS50P2 ———Answer is “Invalid” but “valid” in My case.

7. PI3.14

8. H

9. OUTATIME

Yep, only the first 3 should return “Valid“ Others must return “Invalid”.

My Code :

def main():
    plate = input("Plate: ")
    if is_valid(plate):
        print("Valid")
    else:
        print("Invalid")
def is_valid(s):

    digits = ""
    for char in s:
        if char.isdigit():
            digits += char
        else:
            digits += ""

    punctuation = ""
    for char in s:
        if not char.isalnum():
            punctuation += char
        else :
            punctuation += ""

    if not s[0:2].isalpha():
        return False
    elif len(s) < 2 or len(s) > 6:
        return False
    elif len(punctuation) > 0:
        return False
    elif len(digits) > 0:
        if digits[0] == "0":
            return False
        else: 
            return True
    else:
        return True

main()

You can copy it to your code editors and try other methods to solve it, if you do get it right on all 9 Examples or maybe just have some advice for me then please contact!

LinkedIn - https://www.linkedin.com/in/saddab-ansari-809b46367
or Comment Here below this post as well…!

Thank You For Reading and Do Help me!