Course Schedule 1

Chetan DattaChetan Datta
2 min read

Table of contents

Problem

There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [a<sub>i</sub>, b<sub>i</sub>] indicates that you must take course b<sub>i</sub> first if you want to take course a<sub>i</sub>.

For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.

Return true if you can finish all courses. Otherwise, return false. (link)

Example 1:

Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take. 
To take course 1 you should have finished course 0. So it is possible.

Example 2:

Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take. 
To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

Constraints:

  • 1 <= numCourses <= 2000

  • 0 <= prerequisites.length <= 5000

  • prerequisites[i].length == 2

  • 0 <= a<sub>i</sub>, b<sub>i</sub> < numCourses

  • All the pairs prerequisites[i] are unique.

Solution

This is an application of a topological sort problem.

BFS

class Solution {
    public boolean canFinish(int numCourses, int[][] prerequisites) {
        List<List<Integer>> adjList = createAdjList(numCourses, prerequisites);
        int[] indegrees = createIndegrees(numCourses, prerequisites);
        Queue<Integer> queue = createQueue(indegrees);
        List<Integer> order = new ArrayList<>();

        while(!queue.isEmpty()){
            int vertex = queue.poll();
            order.add(vertex);
            for(int edgeVertex : adjList.get(vertex)){
                indegrees[edgeVertex] -= 1;
                if(indegrees[edgeVertex]==0){
                    queue.add(edgeVertex);
                }
            }
        }

        return order.size() == numCourses;
    }

    private Queue<Integer> createQueue(int[] indegrees){
        Queue<Integer> queue = new ArrayDeque<>();
        for(int i=0; i<indegrees.length; i++){
            if(indegrees[i]==0){
                queue.add(i);
            }
        }
        return queue;
    }


    private int[] createIndegrees(int numCourses, int[][] prerequisites){
        int[] indegrees = new int[numCourses];

        for(int[] edge : prerequisites){
            indegrees[edge[0]]+=1;
        }
        return indegrees;
    }

    private List<List<Integer>> createAdjList(int numCourses, int[][] prerequisites){
        List<List<Integer>> adjList = new ArrayList<>();
        for(int i = 0; i<numCourses; i++){
            adjList.add(new ArrayList<>());
        }
        for(int[] edge : prerequisites){
            adjList.get(edge[1]).add(edge[0]);
        }
        return adjList;
    }

}
0
Subscribe to my newsletter

Read articles from Chetan Datta directly inside your inbox. Subscribe to the newsletter, and don't miss out.

Written by

Chetan Datta
Chetan Datta

I'm someone deeply engrossed in the world of software developement, and I find joy in sharing my thoughts and insights on various topics. You can explore my exclusive content here, where I meticulously document all things tech-related that spark my curiosity. Stay connected for my latest discoveries and observations.