Course Schedule 1

Problem
There are a total of numCourses
courses you have to take, labeled from 0
to numCourses - 1
. You are given an array prerequisites
where prerequisites[i] = [a<sub>i</sub>, b<sub>i</sub>]
indicates that you must take course b<sub>i</sub>
first if you want to take course a<sub>i</sub>
.
For example, the pair [0, 1]
, indicates that to take course 0
you have to first take course 1
.
Return true
if you can finish all courses. Otherwise, return false
. (link)
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0. So it is possible.
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
Constraints:
1 <= numCourses <= 2000
0 <= prerequisites.length <= 5000
prerequisites[i].length == 2
0 <= a<sub>i</sub>, b<sub>i</sub> < numCourses
All the pairs prerequisites[i] are unique.
Solution
This is an application of a topological sort problem.
BFS
class Solution {
public boolean canFinish(int numCourses, int[][] prerequisites) {
List<List<Integer>> adjList = createAdjList(numCourses, prerequisites);
int[] indegrees = createIndegrees(numCourses, prerequisites);
Queue<Integer> queue = createQueue(indegrees);
List<Integer> order = new ArrayList<>();
while(!queue.isEmpty()){
int vertex = queue.poll();
order.add(vertex);
for(int edgeVertex : adjList.get(vertex)){
indegrees[edgeVertex] -= 1;
if(indegrees[edgeVertex]==0){
queue.add(edgeVertex);
}
}
}
return order.size() == numCourses;
}
private Queue<Integer> createQueue(int[] indegrees){
Queue<Integer> queue = new ArrayDeque<>();
for(int i=0; i<indegrees.length; i++){
if(indegrees[i]==0){
queue.add(i);
}
}
return queue;
}
private int[] createIndegrees(int numCourses, int[][] prerequisites){
int[] indegrees = new int[numCourses];
for(int[] edge : prerequisites){
indegrees[edge[0]]+=1;
}
return indegrees;
}
private List<List<Integer>> createAdjList(int numCourses, int[][] prerequisites){
List<List<Integer>> adjList = new ArrayList<>();
for(int i = 0; i<numCourses; i++){
adjList.add(new ArrayList<>());
}
for(int[] edge : prerequisites){
adjList.get(edge[1]).add(edge[0]);
}
return adjList;
}
}
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Written by

Chetan Datta
Chetan Datta
I'm someone deeply engrossed in the world of software developement, and I find joy in sharing my thoughts and insights on various topics. You can explore my exclusive content here, where I meticulously document all things tech-related that spark my curiosity. Stay connected for my latest discoveries and observations.